Question

The points (3,2), (2,3) w.r.t the circle
x² + y² = 12 are​

Answer 1

Answer:

they both lies outside the circle as when we put these points in the eq we get positive number.

they may be conjugation points

Answer 2

Concept

Let x²+y²=c is the equation of a circle

then the conditions for a point (a,b) to lie inside the circle is

a²+b²-c<0

and the conditions for a point (a,b) to lie outside>the circle is

a²+b²-c<0

Given

The equation of circle = x² + y² = 12

To Find,

The position of points  (3,2) and (2,3) with respect to the circle.

Solution,

Check for the point (3,2).

Substitute x=3 and y=2 in the equation of circle

then 3²+2²-12=1 >0

Since the point (3,2) lie outside the circle.

Check for the point (2,3).

Substitute x=2 and y=3 in the equation of circle

then 2²+3²-12=1 >0

Since the point (2,3) lie outside the circle.

Hence, the points (3,2) and (2,3) lie outside the circle.