The points (-5, 1), (1, p),(4, -2) arecollinear then the value of P
Answers
Answered by
2
Answer:
The points (-3,9), (1,p), (4,-5) are collinear if Its determinant value is 0. => |-3 9 1|. |1 p 1| = 0. | 4 -5 1|. => (-3)*(p+5) -9(1-4) +1(-5-4p) = 0.
Similar questions