Question

The points (7,2) (-1,0) lie on a line

Answer 1

Answer:

2x-8y-4=0

Step-by-step explanation:

here is the solution:

$\frac{2 - 0}{7 + 1} = \frac{y - 0}{x - 2}$

$\frac{2}{8} = \frac{y}{x - 2}$

$2(x - 2) = 8y$

$2x - 4 = 8y$

$2x - 8y - 4 = 0$

dividing the above equation by 2,

$x - 4y - 2 = 0$

Answer 2

The required equation of line is $4y=x+1$

Step-by-step explanation:

Given : The points (7,2) (-1,0) lie on a line.

To find : The equation of line ?

Solution :

The slope of the line passing through two points $(x_1,y_1),(x_2,y_2)$ is given by

$m=\frac{y_2-y_1}{x_2-x_1}$

Here, $(x_1,y_1)=(7,2)$ and $(x_2,y_2)=(-1,0)$

Substituting the values ,

$m=\frac{0-2}{-1-7}$

$m=\frac{-2}{-8}$

$m=\frac{1}{4}$

Point slope form of a line is given by $y-y_1=m(x-x_1)$

$y-2=\frac{1}{4}(x-7)$

$4y-8=x-7$

$4y=x+1$

Therefore, the required equation of line is $4y=x+1$

#Learn more

The points (7, 2) and (-1, 0) lie on a line –

1. 7y = 3x-7

2. 4y = x+1 3.

Y = 7x+7

4. X = 4y+1

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