The points A(0,3), B(-2, a) and C(-1,4) are the vertices of a right angled triangle at A. Find the value of a.
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Answered by
213
Hey there!
Length of AB =√[(-2-0)²+(a-3)²]=√4+(a-3)²
Length of BC=√1²+(4-a)²=√1+4-a²
Length of CA=√1²+1²=√2
BC²=AC²+AB²
1+(4-a)²=2+4+(a-3)²
1+16+a²-8a=6+a²+9-6a
17+a²-8a=15+a²-6a
2+a²-a²=-6a+8a
2a=2
a=1
hope helped!
Length of AB =√[(-2-0)²+(a-3)²]=√4+(a-3)²
Length of BC=√1²+(4-a)²=√1+4-a²
Length of CA=√1²+1²=√2
BC²=AC²+AB²
1+(4-a)²=2+4+(a-3)²
1+16+a²-8a=6+a²+9-6a
17+a²-8a=15+a²-6a
2+a²-a²=-6a+8a
2a=2
a=1
hope helped!
Answered by
51
Answer:
Step-by-step explanation: Q--- 4(i)
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