the points (a+1, 1),(2a+1, 3)and (2a+2, 2a) are collinear then the values of a are
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if it is collinear then area of triangle will be zero ok so putting the value in 1/2[a+1(3-2a)+2a+1(2a+1)+2a+2(1-3)]
when we solve it we will get the answer
when we solve it we will get the answer
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