The points a(1,-2) , b(2,3) , c(k,2) and d(-4,-3) are the vertices of parallelogram. find the value of k and the altitude of parallelogram corresponding to the side ab
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Value of k is 9 or -5
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Answer:
Given :
Vertices of a parallelogram are A ( 1 , - 2 ) , B ( 2 , 3 ) , C ( k , 2 ) and D ( - 4 , - 3 ).
We know Diagonal of parallelogram bisect each other .
Midpoint of AC = mid point of BD
= > ( 1 + k / 2 , -2 + 2 / 2 ) = ( - 4 + 2 / 2 , - 3 + 3 / 2 )
= > 1 + k / 2 = - 2 / 2
= > 1 + k = - 2
= > k = - 3 .
Therefore , the value of k is - 3 .
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