The points
A (12,8), B(-2,2) and (6,0) are the
vertices of a right - angled triangle at c. find a
Answers
Answered by
0
Answer:
Given vertices
A
(
12
,
8
)
,
B
(
−
2
,
6
)
,
&
C
(
6
,
0
)
−−→
A
B
=
√
(
12
+
2
)
2
+
(
8
−
6
)
2
=
√
200
−−→
B
C
=
√
(
−
2
−
6
)
2
+
(
6
−
0
)
2
=
10
−−→
C
A
=
√
(
12
−
6
)
2
+
(
6
−
0
)
2
=
10
−−−−→
(
A
B
)
2
=
200
=
−−−−→
(
B
C
)
2
+
−−−−→
(
C
A
)
2
=
100
+
100
=
200
Hence it's a right triangle.
Also it's an isosceles triangle as
−−→
B
C
=
−−→
C
A
=
√
100
Therefore, CD is a perpendicular bisector of hypotenuse AB and hence
−−→
A
D
=
−−→
B
D
Explanation:
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