The points A(3,2), B(0,5), D(0,-1) are the three vertices of a square ABCD. Plot these
Points on a graph paper and hence find the co-ordinates of the vertex C.
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Answers
Given : The points A(3,2), B(0,5), D(0,-1) are the three vertices of a square ABCD.
To Find : Plot these Points on a graph paper
find the co-ordinates of the vertex C.
Solution:
A(3,2), B(0,5), D(0,-1)
BD is diagonal
B & D are on Y axis
Diagonal BD is on y axis
Hence Diagonal AC will be parallel to x axis
A (3,2)
=> C = (x , 2 )
Diagonal bisect Each other
Mid point of BD = 0 , 2
Mid point of AC = (3 + x)/2 , (2 + 2)/2
(3 + x)/2 = 0
=> x = - 3
Hence C = ( - 3 , 2)
co-ordinates of the vertex C. are ( - 3 , 2)
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the three vertices of a parallelogram ABCD taken in order are a (1, -2)
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![](https://hi-static.z-dn.net/files/d6f/bc16e2f279c3af69f289e9e7a72252d8.png)
Answer:
I’ve plotted the solution on the graph
![](https://hi-static.z-dn.net/files/daa/8eba912d74c62aba1cd6a385ec5fcdfa.jpg)