Math, asked by mimi0701, 9 months ago



The points A(3,2), B(0,5), D(0,-1) are the three vertices of a square ABCD. Plot these
Points on a graph paper and hence find the co-ordinates of the vertex C.
27​

Answers

Answered by amitnrw
8

Given :  The points A(3,2), B(0,5), D(0,-1) are the three vertices of a square ABCD.  

To Find : Plot these  Points on a graph paper

find the co-ordinates of the vertex C.

Solution:

A(3,2), B(0,5), D(0,-1)

BD  is diagonal

B & D are  on Y axis

Diagonal BD is on y axis

Hence Diagonal AC will be  parallel to x axis

A (3,2)

=> C = (x , 2 )

Diagonal bisect Each other

Mid point of BD  =  0 , 2

Mid point of AC  =  (3 + x)/2  , (2 + 2)/2

(3 + x)/2 = 0

=> x = - 3

Hence C = ( - 3 , 2)

co-ordinates of the vertex C. are  ( - 3 , 2)

Learn More:

prove that two opposite vertices of a parallelogram are equal ...

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the three vertices of a parallelogram ABCD taken in order are a (1, -2)

https://brainly.in/question/8511174

Attachments:
Answered by aaryajadhav21
0

Answer:

I’ve plotted the solution on the graph

Attachments:
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