Question

The points A(4, −1), B(6, 0), C(7, 2) and D(5, 1) are the vertices of a rhombus. Is ABCD also a square?

Answer 1

Answer:

Step-by-step explanation:

et A (4,-1) B (6,0) C (7,2) and D (5,1)

first find length of side

AB=root {(2)^2+(1)^2}=root5

BC=root {(1)^2+(2)^2}=root5

CD=root {(2)^2+(1)^2}=root5

AD=root {(1)^2+(2)^2}=root5

here we see

AB=BC=CD=AD

hence ABCD is rhombus

now AC=root {(3)^2+(3)^2}=3root2

here AC^2=BC^2+CA^2 isn't possible so

ABCD isn't square this is only rhombus