The points A(4,-2) B(7,2) C(0,9) and D(-3,5) form a parallelogram. Find the length of the altitude of the parallelogram on the base AB.
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Given A(4,-2) B(7,2) C(0,9) and D(-3,5).
Area of the triangle ABC = 1/2 (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)
= 1/2(4(2-9) + 7(9+2)
= 49/2.
Area of parallellogram = 2 * 49/2 = 49 square units.
Base of the parallelogram AB = root(x1 - x2)^2 + (y1 - y2)^2
= root (4 - 7)^2 + (-2-2)^2
= root 9 + 16
= root 25
= 5.
The height of the parallelogram = 49/5.
Area of the triangle ABC = 1/2 (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)
= 1/2(4(2-9) + 7(9+2)
= 49/2.
Area of parallellogram = 2 * 49/2 = 49 square units.
Base of the parallelogram AB = root(x1 - x2)^2 + (y1 - y2)^2
= root (4 - 7)^2 + (-2-2)^2
= root 9 + 16
= root 25
= 5.
The height of the parallelogram = 49/5.
aradhyachaudhry:
of a triangle
Ohk
when only its coordinates are given
Area of triangle formula in coordinate geometry
I forgot about that formula :p
ya
ohh
All right thanks a lot!
no problem
:)
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