The points A(4, 7), B(p, 3) and C(7, 3) are the vertices of a right triangle,
right-angled at B. Find the value of p.
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A(4,7), B(p,3) & c (7,3) are vertices of right angle triangle then u
using Pythagoras theorem
(AC)
2
=(AB)
2
+(BC)
2
(7−4)
2
+(3−7)
2
=(p−4)
2
+(3−7)
2
+(p−7)
2
+(3−3)
2
9+16=(p−4)
2
+16+(p−7)
2
9=p
2
+16−8p+p
2
+49−14p
2p
2
−22p+56=0
p
2
−11p+28=0
p
2
−7p−4p+28=0
(p-4)(p-7)=0
Hence p-4=0 & p-7=0
[p=4,7
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