The points A,B and C are collinear and AB = BC . If the co - ordinates of A, B and C are ( 3,a) (1,3) and (6,4) respectively ,then find the values of a and c .
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Step-by-step explanation:
that means b Is mid point of ab.
\begin{gathered}( \frac{3 + b}{2} .. \frac{a + 4}{2}) \\ = (1..3) \\ \\ 3 + b = 2 \\ b = - 1 \\ a + 4 = 6 \\ a = 2 \end{gathered}
(
2
3+b
..
2
a+4
)
=(1..3)
3+b=2
b=−1
a+4=6
a=2
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