The points A , B and C have the following position vectors with respect to an origin O.
OA= 2i + j -2k
OB= 2i - j + 2k
OC= i + 3j + 3k
Find the vector equation of the line (BC)
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Given info : The points A , B and C have the following position vectors with respect to an origin O.
OA= 2i + j -2k
OB= 2i - j + 2k
OC= i + 3j + 3k
To find : the equation of line BC.
Solution : from triangle rule,
OB + BC = OC [ see figure ]
so, BC = OC - OB
⇒BC = (i + 3j + 3k) - (2i - j + 2k)
⇒BC = (1 - 2)i + (3 + 1)j + (3 - 2)k
⇒BC = -i + 4j + k
Therefore the equation of line BC is -i + 4j + k.
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