The points A, B, and C on the circle with center O in the figure are such that ∠BOC = 30o and ∠AOB = 60o . If D is a point on the circle other than the arc ABC, find ∠ADC.
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According to theorem of circles ∠AOC=2∠ADC ..(i) ∠AOC=∠AOB+∠BOC=60 ∘ +30 ∘ =90 ∘ from equation(i) 90 ∘ =2∠ADC
∠ADC=45 ∘
∠ADC=45 ∘
hope it helps uhh
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