Question

The points A, B and Care (4, 0),
(0, 6) respectively. Find the equations of AB
and BC.
If AB cuts the y-axis at P and BC cuts the
x-axis at Q, find the co-ordinates of P
and Q​

Answer 1

Answer:

For the line AB :

Slope of AB = m =

2-02-4=2-2=-1

(x1, y1) = (4, 0)

Equation of the line AB is

y − y1 = m (x − x1)

y − 0 = −1 (x − 4)

y = − x + 4

x + y = 4 ....(1)

For the line BC :

Slope of BC =

m6-20-2=4-2=-2

(x1, y1) = (2, 2)

Equation of the line BC is

y − y1 = m(x − x1)

y − 2 = −2 (x − 2)

y − 2 = − 2x + 4

2x + y = 6 ....(2)

Given that AB cuts the y-axis at P. So, the abscissa of point P is 0.

Putting x = 0 in (1), we get, y = 4

Thus, the co-ordinates of point P are (0, 4).

Given that BC cuts the x-axis at Q. So, the ordinate of point Q is 0. Putting y = 0 in (2), we get,

2x = 6

⟹ x = 3

Thus, the co-ordinates of point Q are (3, 0).

Answer 2

hope this will help u !!!!!!!!!!