the points A; b; c; d; e; f are situated on a straight line in this order. The following distancs on tjis line are know af=35; av= 12; bd=11; ce= 12 and df= 16
how long is the distance be??
Answers
Answered by
8
Answer: 16
Step-by-step explanation:
Ef=af-ae
=af-(ac+ce)
=35-(12+12)
=35-24=11
Ab=af-bf
=af-( bd+df)
=35-(11+16)
= 35-27=8
Be= af-ab-ef
=35-8-11
=16
Please mark me as brainliest
Step-by-step explanation:
Ef=af-ae
=af-(ac+ce)
=35-(12+12)
=35-24=11
Ab=af-bf
=af-( bd+df)
=35-(11+16)
= 35-27=8
Be= af-ab-ef
=35-8-11
=16
Please mark me as brainliest
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Anonymous:
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Answered by
0
16 is your answer. lease mar me as brainliest
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