The points A, O and B are collinear points. Find the value of x in the following diagrams.
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In each case the given angles are on a line, hence their sum should be 180°
(1)→2x+10+3x-10+40=180
→5x+40=180
→5x=140
→x=28
(2)→28+x+90+36=180
→x+154=180
→x=26
Hope my ans was easy for u
(1)→2x+10+3x-10+40=180
→5x+40=180
→5x=140
→x=28
(2)→28+x+90+36=180
→x+154=180
→x=26
Hope my ans was easy for u
Saanvipriya:
thanx
Answered by
0
Heya Dear !
______________________________________________________________
1) here
2x + 10 + 3x- 10 +40 = 180 [LPA's]
5x + 40 = 180
5(x+8) = 180
x+ 8 = 36
x = 28 °
2.
28 + x + 36+ 90 = 180 [LPA's]
154 + x = 180
x = 26°
______________________________________________________________
1) here
2x + 10 + 3x- 10 +40 = 180 [LPA's]
5x + 40 = 180
5(x+8) = 180
x+ 8 = 36
x = 28 °
2.
28 + x + 36+ 90 = 180 [LPA's]
154 + x = 180
x = 26°
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