Question

The points of intersection of 2x - 3y = 6 with the coordinate axes are 1 point (3,0) & (0,4) (3,0) & (0,-2) (3,0) & (0,2) (5,0) & (0,-2)

Answer 1

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Step-by-step explanation:

$line \: \: 2x - 3y = 6 \\ if \: it \: intersect \: with \: x \: axis \: then \: y = 0 \\ \\ 2x - 3(0) = 6 \\ 2x = 6 \\ x = 3 \\ \\ if \: it \: intersect \: with \: y \: axis \: then \: x = 0 \\ \\ 2(0) - 3y = 6 \\ - 3y = 6 \\ y = - 2 \\ \\ therefore \: points \: are \: (3.0) \: and \: (0. - 2)$

Here's The Answer My Friend....

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Answer 2

Answer:

(3,0) and (0,-2)

Solution:

Here,

The given equation of line is ;

2x - 3y = 6 ------(1)

We need to find the points of intersection of the given line with the coordinates axes.

★ Point of the intersection of the given line with x-axis :

We know that ,

At x-axis , y-coordinate is zero .

Thus,

Putting y = 0 in eq-(1) , we get ;

=> 2x - 3•0 = 6

=> 2x = 6

=> x = 6/2

=> x = 3

Hence,

The given line would intersect the x-axis at the point (3,0) .

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★ Point of the intersection of the given line with y-axis :

We know that ,

At x-axis , x-coordinate is zero .

Thus,

Putting x = 0 in eq-(1) , we get ;

=> 2•0 - 3y = 6

=> -3y = 6

=> y = 6/-3

=> y = -2

Hence,

The given line would intersect the y-axis at the point (0,-2)

Hence,

The points of intersection of 2x - 3y = 6 with the coordinate axes are :

(3,0) and (0,-2)