Question

The points on the curve y3 +3x2=12y where the tangent is vertical

Answer 1

Answer:

\(y^3 + 3x^2 = 12y\) \(\Rightarrow\frac{dy }{dx}=\frac{6x}{3\left(4-y^2\right)}.\) For vertical tangents, y = ± 2. But for y = –2