Question

the points on the x axis which is equidistant from a (-1, 2) and b(5, 4) is​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

ANSWER

AC=BC (Equidistance)

AC^ 2=BC^ 2

(x−5) ^2+(0−4)^ 2=(x+2)^ 2+(0−3)^ 2

x ^2−10x+25+16=x ^2+4+4x+9

−14x+41−13=0

−14x+28=0

=14x=−28

x=28/14

x=2

These the coordinates are (2,0)

solution