The points on y-axis at a distance of 13 units from point (-5, 7) are :
(a) (0,5) (0, 19)
(b) (0,5) (0, -19)
(c) (0, -5) (0, -19)
(d) (0, -5) (0, 19)
Answers
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Answer:
(0+5)^2+(y1-7)^2=13^2
25+(y1-7)^2=169
y1-7=√(169-25)=+12 or -12
y1=12+7=19 or -12+7=-5
points are 0,19 and 0,-5. (d)
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