The points P(2,9) Q(a,5) R(5,5) are the vertices of a triangle PQR right angles at Q.bfind the value of a and hence the area of the triangle PQR
Answers
Answered by
15
by distance formula find the distance of PQ, PR and QR
Since, the triangle is right angled
by applying Pythagoras theorem and solving it we get a quadratic equation in terms of 'a'
a²-5a+10=0
we get two values of a
a=5 or a=2
if a = 5 then side QR length is zero
therefore, a= 2
and area of triangle is 6 sq unit
Since, the triangle is right angled
by applying Pythagoras theorem and solving it we get a quadratic equation in terms of 'a'
a²-5a+10=0
we get two values of a
a=5 or a=2
if a = 5 then side QR length is zero
therefore, a= 2
and area of triangle is 6 sq unit
Answered by
18
Answer:
Step-by-step explanation:
Hope this help......
Attachments:
Similar questions