the points(t,2t)(-2,6)and (3,1)are collinear at
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Three points are collinear it means,
AB + AC = BC
Let,
A(t,2t) , B(-2,6) , C(3,1)
X1 = t, X2 = -2 ,Y1= 2t ,Y2 = 6
AB = under root (X2-X1)² + (Y2-Y1)²
Put value and solve after this find AC.
X1 = t ,X2 = 3 ,Y1 = 2t , Y2 = 1
AC = UNDER ROOT (X2-X1)² + (Y2-Y1)²
put values and solve u will get AC after this find BC
X1 = -2 , X2 = 3 ,Y1 = 6 , Y2 = 1
Therefore,
BC = under root (X2-X1)² + ( Y1-Y2)²
PUT VALUES AND SOLVE AND FIND AC , AB , BC.
IF AC+AB = BC THEN THESE POINTS ARE COLLINEAR
AB + AC = BC
Let,
A(t,2t) , B(-2,6) , C(3,1)
X1 = t, X2 = -2 ,Y1= 2t ,Y2 = 6
AB = under root (X2-X1)² + (Y2-Y1)²
Put value and solve after this find AC.
X1 = t ,X2 = 3 ,Y1 = 2t , Y2 = 1
AC = UNDER ROOT (X2-X1)² + (Y2-Y1)²
put values and solve u will get AC after this find BC
X1 = -2 , X2 = 3 ,Y1 = 6 , Y2 = 1
Therefore,
BC = under root (X2-X1)² + ( Y1-Y2)²
PUT VALUES AND SOLVE AND FIND AC , AB , BC.
IF AC+AB = BC THEN THESE POINTS ARE COLLINEAR
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