Question

the points (t,2t),(-2,6) and (3,1) are collinear then t=

Answer 1

x1(y2-y3)+x2(y3-y1)+x3(y1-y2) =0
t(6-1)-2(1-2t)+3(2t-6) =0
6t-t-2+4t+6t-18=0
15t=20
t=20/15
t=4/3

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Answer 2

Answer:

Step-by-step explanation:

If points are collinier then

Ar. Of triangle=0

1/2{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}=0

t(6-1)+(-2)(1-2t)+3(2t-6)=0

5t-2+4t+6t-18=0

15t-20=0

15t=20

t=20/15

t=4/3....or....t=1.33

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