Question

The points which divides the line segment of points P(-1,7) and (4,-3) in the ration of 2:3 is: *

1 point

(a)(-1,3)

(b)(-1,-3)

(c)(1,-3)

(d)(1,3)​

Answer 1

Answer:

(d)

(1,3)

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given:P(-1,7) and Q(4,-3)

To find:Find the point which divides the line segment in ratio 2:3.

(a)(-1,3)

(b)(-1,-3)

(c)(1,-3)

(d)(1,3)

Solution:

Tip: Section formula

If line segment by joining the points P(x1,y1) and Q(x2,y2) is divided by the S(x,y) in m:n ratio,then coordinates of S are given by

$x = \frac{mx_1 + nx_2}{m + n} \\ \\ y = \frac{my_1 + ny_2}{m + n}$

Here,

Points are P(-1,7) and Q(4,-3) ,ratio is 2:3

apply the values in the formula

$x = \frac{2(4) + 3( - 1)}{2 + 3}$

$x = \frac{8 - 3}{5}$

$x = \frac{5}{5}$

$x = 1$

by the same way,find y

$y = \frac{3 (7)+ 2( - 3)}{3 + 2}$

$y = \frac{21 - 6}{5}$

$y = \frac{15}{5}$

$y = 3$

Coordinates of S are (1,3).

Option D is correct.

Final answer:

Coordinates of S are (1,3).

Option D is correct.

Hope it helps you.

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