Question

The poissons ratio of a material is 0.4 when a force is applied to a wire of this material does an increase of length by 2% the percentage change in its volume is

Answer 1

Answer:Note: I am writing sigma as ⊂.

Given Poisson's ratio (⊂) = 0.5.

Here, density is constant and hence change in volume is 0.

Given that there is a decrease in cross-sectional area by 4%

So, (dA/A) = 4.

We know that dA/A = 2 * (dr/r).

= > 4 = 2 * (dr/r)

= > 2 = (dr/r).

Hence,

= > dl/l

= > (dr/r)/⊂

= > 2/0.5

= > 4.

Therefore, the % increase in length = 4% (or) 0.04.