the polar form of √2 + √2i is
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Step-by-step explanation:
z = a+bi to polar form
z = r (cosϴ+ i sinϴ)
we have two relations.
1. Modulus: r = √[(a²) + (b²)]
r = √[(√2)² + (√2)²]
= 2
2. Angle formed with the positive x-axis:
ϴ = arctan (b/a)
ϴ= arctan(√2/√2) = 45° since the point is in the second quadrant.
Then;
z = 2 (cos 45° + i sin 45°)
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