Question

the polar form of complex number z=i-√3 =​

Answer 1

Answer:

2[cos(5π/6) + i*sin(5π/6)]

Step-by-step explanation:

The polar form of a complex number (z = x + yi) is

z = r(cosβ + isinβ) and

r = | z | = √(x² + y²)

~~~~~~~~~

z = - √3 + i

r = √[(- √3)² + 1²] = 2

Find β

x < 0 , then cosβ = x/r = (- √3)/2 ⇒ β = arccos (- √3)/2) = 5π/6

Therefore, the polar form of (- √3 + i) is 2[cos(5π/6) + i*sin(5π/6)]