The polar form of (i^25)^3 is
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Answer:
z=(i
25
)
3
=i
75
=i
4×18+3
=(i
4
)
18
.i
3
=(1)
18
.i
2
×i
=−i
polar form of z=r(cosθ+isinθ)
=1[cos(−
2
π
)+isin(−
2
π
)]
=1[cos(
2
π
)−isin(
2
π
)]
=cos
2
π
−isin
2
π
Step-by-step explanation:
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