the polar form of (i^25)^3 is
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Given Complex number is Z = (i25)3
⇒ Z = i75
⇒ Z = i74.i
⇒ Z = (i2)37.i
We know that i2 = - 1
⇒ Z = ( - 1)37.i
⇒ Z = ( - 1).i
⇒ Z = - i
⇒ Z = 0 - i
We know that the polar form of a complex number Z = x + iy is given by Z = |Z|(cosθ + isinθ)
Where,
|Z| = modulus of complex number =
θ = arg(z) = argument of complex number =
Now for the given problem,
⇒
⇒
⇒
⇒ |z| = 1
⇒
Since x>0,y<0 complex number lies in 4th quadrant and the value of θ will be
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