Question

the polar of the point (-2,3) with respect to x^2+y^2-4x-6y+5​

Answer 1

Step-by-step explanation:

S1 = 0

= x(-2) + y(3) - 2x -2(-2) - 3y - 3(3) + 5 = 0

= -2x+3y-2x-3y +9-9 = 0

2(3y-2x) = 0

2x-3y = 0

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Answer 2

Given, x = -2 and y = 3 Putting the value of x and y in the polynomial

x²+y² - 4x-6y + 5

= (-2)²+(3)² - 4× (-2) - 6×3 + 5

= 4 + 9 + 8 - 18 + 5

= 36+8 = 44