the
pole
is
10
m
.
The
man's
eye
is
2
m
above
the
ground
.
He
observes
the
angle
of
elevation
C
ro
8. With reference to the given
figure, a man stands on the
ground at point A,
which is on the
horizontal
plane as B, the foot
of the vertical pole
BC. The height of
D
same
2m
A
B
2
of C, the top of the pole, as t°, where tan
Calculate : (i) the distance AB in
5
metres; (ii) angle of elevation of the top of the
pole when he is standing 15 metres from the
pole.
Answers
Answer:
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Step-by-step explanation:
Man eye is 2m above the ground.
Pole height = 10 m
hence height of top of the pole above man eye = 10 - 2 = 8 m
Tan ( angle of elevation ) = height of top of the pole above man eye / horizontal distance
=> Tan (x) = 8 / AB
=> 2/5 = 8/AB
=> AB = 20
the distance AB in metres = 20
Learn more:
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