Question

The pole of the line 8x-2y=11 with respect to the circle 2x^2+2y^2=11 is​

Answer 1

ANSWER

I assume that you know what are polar and pole

and basic terminology such as what is T = 0.

• To find the pole of a line first assume the coordinate of pole some constant a, b or h, k.
• find equation of polar which is given by T = 0
• now this equation of polar represent the same equation as line.
• then by comparing the coefficient of similar terms we can get the coordinate of pole.

In general the pole of line lx+my+n = 0 wrt circle

${x}^{2} + {y }^{2} = {a}^{2}$

will be

$( \frac{ - l {a}^{2} }{n} \:. \: \frac{ - m {a}^{2} }{n} )$

here " . " is ", " operator

since,

a^2 = 11/2

l = 8

m = -2

n = -11

so pole is

( 4,-1)

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