Question

The poles of hight 10 cm and 15 cm vertical ly on a plane ground if the distance between their feet in is 5√3find the distance between their top
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Answer 1

Answer:

The distance between their tops is 10 m

Step-by-step explanation:

Height of tower AB = 10 m

Height of tower CD = 15 m

The distance between their feet i.e. BD = 5√3 m

AB = ED = 10 m

CD = CE+ED

15 = CE +10

CE = 15-10 = 5

AE= BD = 5√3 m

In ΔACE

Hypotenuse² = perpendicular² + Base²

AC² =CE²+ AE²

AC² = 5² +( 5√3)²

AC = √5²+(5√3)²

AC =  10

Hence  the distance between their tops is 10 m.

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