Question

The poles of the function f(z)= Sinz/cosz are at?​

Answer 1

Answer:

the

singularities of cotz = cosz sinz are z = nπ, n = 0,±1,±2,... They are all simple poles, but only the singularity at z = 0 is inside the cirlce |z| = 3. Now we could expand g(z) = z/sinz as a Taylor series about z = 0.