Question

the polynials ax^3-3x^2+4 and 2x^3-5x+a when divided by (x-2) leave the remainder p and q respectively if p-29=41 then find the value of a


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Answer 1

Answer:

a=9.75

Step-by-step explanation:

Using remainder theorem, substitute x= 2

Remainder p = a2³-3×2²+4= 8a -8

q= 2×2³ -5 ×2 +a = 6+a

p-29 = 41

8a-8-29=41

8a = 78

a= 78/8 = 39/4=9.75