Question

the polynomial 2x cube - kx square + 7 xsquare
+ 1 when divided by x minus 2 leaves remainder 5 then find the value of k​

Answer 1

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Answer 2

The value of k is 10.

Step-by-step explanation:

Remainder theorem: If a polynomial P(x) is divided by (x-c), then the remainder is P(c).

The given polynomial is

$P(x)=2x^3-kx^2+7x^2+1$

It is given that the reminder is 5 when P(x) is divided by x-2.

Using remainder theorem P(2)=5.

Substitute x=2 in the above polynomial.

$P(2)=2(2)^3-k(2)^2+7(2)^2+1$

$P(2)=16-4k+28+1$

Substitute P(2)=5.

$5=45-4k$

$4k=45-5$

$4k=40$

$k=10$

Therefore, the value of k is 10.

#Learn more

Polynomial 3 x cube minus 5 x square + kx - 2 and minus x cube minus x square + 7 x + K leaves the same remainder when divided by X + 2 find the value of k​.

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