The polynomial 2xcube-kxsquare + 7x-1 when divided by x-1 leaves the remainder 3 . Then find the value of k
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Answer:
zero are
x-1 = 0
x = 1
s0, 2x³-kx²+7x-1 = 3
==> 2(1)³-k(1)²+7(1)-1 = 3
==> 2-k+7-1 = 3
==> 9-k = 3
==> -k = -9/3
==> k = 3
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