Question

the polynomial 3 x cube + x square + 3 X + 5 and 4 x cube + x square - 2 X + a leaves remainder R1 and R2 when divided by x minus 2 respectively if R1 minus R2 equals to 9 find the value of a​

Answer 1

Hello Mate!

Let the remainder be R1 and R2 as given :

R1 = ax^3 + 3x^2 - 3

Now, x - 4 => x = 4

R1 = a(4)^3 + 3(4)^2 - 3

R1 = 64a + 48 - 3

R1 = 64a + 45

R2 = 2x^2 - 5x + a

R2 = 2(4)^2 - 5(4) + a

R2 = 32 - 20 + a

R2 = 12 + a

R1 + R2 = 0

64a + 45 + 12 + a = 0

65a = - 57

a = - 57/65

2R1 - R2 = 0

2( 64a + 45 ) - 12 - a = 0

128a + 90 - 12 - a = 0

127a = - 78

a = - 78/127

Answer 2

Answer:

right answer

Step-by-step explanation:

the first one is right

I think so so