Question

The polynomial 3x^2+5x-3 has zeroes alpha and beta , alpha ^2+ beta ^2 is.......
please solve, and don't send uneccesary message​

Answer 1

Answer:

3x²+5x-3=0

x=-5±root 25-4(3(3)/6

x=-5±root25-36/6

x=-5±root-9/6

x=-5±3/6

x=-2/6,x=-8/6

x=-3,x=-4/3

alpha²+beta²

=(-3)²+(-4/3)²

=9+16/9

81+16/9=97/9