Math, asked by kdm0006, 5 hours ago

the polynomial 3x2-ax2+5x-13 and (a+1)x2-7x+5 leave the same remainder when divided by x-3 find the value of a

Answers

Answered by shraddhagulve1234

1

Answer:

多項式

Step-by-step explanation:

多項式3x2-ax2 + 5x-13と（a + 1）x2-7x + 5は、x-3で割ったときに同じ余りを残し、aの値を求めます。

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