Question

the polynomial 3x³+(3a-1)x²-5x+4 and 4x³+5x²-12ax-35 are divided by (x-3) and leaves a same remainder in each case. find the value of a. idiotic answers are not allowed

Answer 1

I feel you question is wrong it should be (x-2) but since u need the answer i think this is correct!
Hope it helps and ya don’t forget to mark me brainlist☺️

Answer 2

Answer:

When $\tt{3x^{3} + (3a-1)x^{2} - 5x + 4}$ is divided by (x - 3):

Remainder = 27a + 61

When $\tt{4x^{3} + 5x^{2} - 12ax - 35}$ is divided by (x - 3):

Remainder = 118 - 36a

Equate the remainders:

27a + 61 = 118 - 36a

=> 63a = 57

=> $\boxed{\sf{a = \frac{19}{21}}}$

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