The polynomial a(x)=x^3+5x^2+2x+3 is divided by b(x)=x^2+mx+1
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Given :- The polynomial a(x)=x^3+5x^2+2x+3 is divided by b(x)=x^2+mx+1 .
Solution :-
I think we need to find quotient and remainder here .
dividing a(x) by b(x) by long division method we get,
x² + mx + 1 ) x³ + 5x² + 2x + 3 ( x + (5 - m)
x³ + mx² + x
(5-m)x² + x + 3
(5-m)x² + mx(5-m) + (5-m)
x - (5mx - m²x) -(5 - m)
→ Quotient = x + (5 - m)
→ Remainder = [x - (5mx - m²x) -(5 - m)] or, (m²x + x - 5mx + m - 5) .
Learn more :-
JEE mains Question :-
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. Find all the zeroes of the polynomial x4
– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.
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