Math, asked by kuchbhi4946, 1 year ago

the polynomial ax^3+3x^2-13 and 2x^3-5x+a are divided by x+2, if the remainder in the each case is same find a

Answers

Answered by tushar1305
2

Please mark it as a brainlist..

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Answered by Anonymous
21

Answer:

Let

 \\  \boxed{ \sf p(x) = ax {}^{3}  + 3 {x}^{2}  - 13} \\

and

 \\  \boxed{ \sf q(x) = 2 {x}^{3}  - 5x + a} \\  \\

be the given polynomials. The remainder when p(x) and q(x) are divided by (x+2) are p(-2) and q(-2) respectively.

By the given condition, we have

  \\  \qquad \sf \: p( - 2) = q( - 2) \\  \\  \\  \implies \sf \: a {( - 2)}^{3}  + 3 {( - 2)}^{2}  - 13 = 2 {( - 2)}^{3}  - 5 \times  \\  \\  \sf \:  - 2 + a \\  \\  \\  \implies \sf - 8a + 12 - 13 =  - 16 + 10 + a \\  \\  \\  \implies \sf - 8 a - 1 = a - 6 \\  \\  \\  \implies \sf - 9 =  - 5 \\  \\  \\   \implies\boxed{ \sf a =  \frac{5}{9} } \\  \\  \\

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