The polynomial ax^3+3x^2-3 and 2x^3-5x+a when divided by (x-4) leaves the same remainder.Find the value of a
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f(x)= ax³+3x²-3
p(x)= 2x³-5x+a
Given that,
leaves the same remainder
f(4) = p(4)
a(4)³+3(4)²-3 = 2(4)³-5(4)+a
64a + 48 - 3 = 128 - 20 + a
63a = 63
a = 1
p(x)= 2x³-5x+a
Given that,
leaves the same remainder
f(4) = p(4)
a(4)³+3(4)²-3 = 2(4)³-5(4)+a
64a + 48 - 3 = 128 - 20 + a
63a = 63
a = 1
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