the polynomial ax cube minus 3xsquare plus 4 and 2xcube when divided by x minus 2 leave the same remainder p and q respectively. if p =-2 and q=4.find value of a. its answer is 4.tell me the whole solution
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hello..
p(x)=ax3-3x2+4
g(x)=2x3-5x+a .. factor of g(x) and p(x) are x-2
p(2)= 8a-12+4=p [Remainder thm.]
= 8a-8=p
g(2)=16-10+a=q
=6+a=q
p-2q=4
8a-8-2(6+a)=4
8a-8-12-2a=4
6a-20=4
6a=24
a=24/6
=4
thank you...
☺
p(x)=ax3-3x2+4
g(x)=2x3-5x+a .. factor of g(x) and p(x) are x-2
p(2)= 8a-12+4=p [Remainder thm.]
= 8a-8=p
g(2)=16-10+a=q
=6+a=q
p-2q=4
8a-8-2(6+a)=4
8a-8-12-2a=4
6a-20=4
6a=24
a=24/6
=4
thank you...
☺
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