the polynomial ax2 +3x2-13 and 2x3-5x+a when divided by (x-2)leaves same remainder. find value of a.
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x-2=0
x=2
p(2)=a2*2+3*2*2-13
p(2)=a4+12-13
p(2)=a4-1.
second case
x=2
2x3-5x+a
2*2*3-5*2+a
12-10+a
2+a
so by adding 1 and 2
a4-1=2+a
a4=1+2+a
a4=3+a
a4-a=3
a3=3
a=3/3
a=1.
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x=2
p(2)=a2*2+3*2*2-13
p(2)=a4+12-13
p(2)=a4-1.
second case
x=2
2x3-5x+a
2*2*3-5*2+a
12-10+a
2+a
so by adding 1 and 2
a4-1=2+a
a4=1+2+a
a4=3+a
a4-a=3
a3=3
a=3/3
a=1.
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