The polynomial ax³+3x²-3 and2x³-5x+a are divided by x-4
and leave the same remainder
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here is your question solved.
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Step-by-step explanation:
X-4=0
Therefore X=0
Substituting the value of x in the equation we get
a(4)^3 + 48 - 3 =0
2(4)^3 - (5)4 + a =0
As the remainders are same,
a(4)^3 + 48 - 5 = 2(4)^3 -5(4) + a
64a + 45 = 128 - 20 + a
64a - a = 108 - 45
63a = 63
a = 63 ÷ 63
a = 1
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