The polynomial bx3 + 3x2 – 3 and 2x3 – 5x + b when divided by x – 4 leave the remainders R1 and R2 respectively. Find the value of b, if 2R1 – R2 = 0.
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Answer:
bx3 + 3x2 – 3 and 2x3 – 5x + b/(x-4)
R1 and R2 is remainder
Step-by-step explanation:
2R1-R2=0
b=6
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