the polynomial equation
x(x+1)+8=(x+2)(x-2)
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Given that: x(x+1)+8=(x+2)(x−2)
By simplifying we get
x^2+x+8=x^2−4
x^2−x^2+x+8+4=0
x+12=0
It is not of the form ax^2+bx+c=0
The variable x is only in the first degree.
∴ It is not a quadratic equation.
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